Optimal. Leaf size=248 \[ -\frac{b f^2 m n \text{PolyLog}\left (2,\frac{f x^2}{e}+1\right )}{8 e^2}-\frac{\left (a+b \log \left (c x^n\right )\right ) \log \left (d \left (e+f x^2\right )^m\right )}{4 x^4}-\frac{f^2 m \log (x) \left (a+b \log \left (c x^n\right )\right )}{2 e^2}+\frac{f^2 m \log \left (e+f x^2\right ) \left (a+b \log \left (c x^n\right )\right )}{4 e^2}-\frac{f m \left (a+b \log \left (c x^n\right )\right )}{4 e x^2}-\frac{b n \log \left (d \left (e+f x^2\right )^m\right )}{16 x^4}+\frac{b f^2 m n \log \left (e+f x^2\right )}{16 e^2}-\frac{b f^2 m n \log \left (-\frac{f x^2}{e}\right ) \log \left (e+f x^2\right )}{8 e^2}+\frac{b f^2 m n \log ^2(x)}{4 e^2}-\frac{b f^2 m n \log (x)}{8 e^2}-\frac{3 b f m n}{16 e x^2} \]
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Rubi [A] time = 0.226004, antiderivative size = 248, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 7, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.269, Rules used = {2454, 2395, 44, 2376, 2301, 2394, 2315} \[ -\frac{b f^2 m n \text{PolyLog}\left (2,\frac{f x^2}{e}+1\right )}{8 e^2}-\frac{\left (a+b \log \left (c x^n\right )\right ) \log \left (d \left (e+f x^2\right )^m\right )}{4 x^4}-\frac{f^2 m \log (x) \left (a+b \log \left (c x^n\right )\right )}{2 e^2}+\frac{f^2 m \log \left (e+f x^2\right ) \left (a+b \log \left (c x^n\right )\right )}{4 e^2}-\frac{f m \left (a+b \log \left (c x^n\right )\right )}{4 e x^2}-\frac{b n \log \left (d \left (e+f x^2\right )^m\right )}{16 x^4}+\frac{b f^2 m n \log \left (e+f x^2\right )}{16 e^2}-\frac{b f^2 m n \log \left (-\frac{f x^2}{e}\right ) \log \left (e+f x^2\right )}{8 e^2}+\frac{b f^2 m n \log ^2(x)}{4 e^2}-\frac{b f^2 m n \log (x)}{8 e^2}-\frac{3 b f m n}{16 e x^2} \]
Antiderivative was successfully verified.
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Rule 2454
Rule 2395
Rule 44
Rule 2376
Rule 2301
Rule 2394
Rule 2315
Rubi steps
\begin{align*} \int \frac{\left (a+b \log \left (c x^n\right )\right ) \log \left (d \left (e+f x^2\right )^m\right )}{x^5} \, dx &=-\frac{f m \left (a+b \log \left (c x^n\right )\right )}{4 e x^2}-\frac{f^2 m \log (x) \left (a+b \log \left (c x^n\right )\right )}{2 e^2}+\frac{f^2 m \left (a+b \log \left (c x^n\right )\right ) \log \left (e+f x^2\right )}{4 e^2}-\frac{\left (a+b \log \left (c x^n\right )\right ) \log \left (d \left (e+f x^2\right )^m\right )}{4 x^4}-(b n) \int \left (-\frac{f m}{4 e x^3}-\frac{f^2 m \log (x)}{2 e^2 x}+\frac{f^2 m \log \left (e+f x^2\right )}{4 e^2 x}-\frac{\log \left (d \left (e+f x^2\right )^m\right )}{4 x^5}\right ) \, dx\\ &=-\frac{b f m n}{8 e x^2}-\frac{f m \left (a+b \log \left (c x^n\right )\right )}{4 e x^2}-\frac{f^2 m \log (x) \left (a+b \log \left (c x^n\right )\right )}{2 e^2}+\frac{f^2 m \left (a+b \log \left (c x^n\right )\right ) \log \left (e+f x^2\right )}{4 e^2}-\frac{\left (a+b \log \left (c x^n\right )\right ) \log \left (d \left (e+f x^2\right )^m\right )}{4 x^4}+\frac{1}{4} (b n) \int \frac{\log \left (d \left (e+f x^2\right )^m\right )}{x^5} \, dx-\frac{\left (b f^2 m n\right ) \int \frac{\log \left (e+f x^2\right )}{x} \, dx}{4 e^2}+\frac{\left (b f^2 m n\right ) \int \frac{\log (x)}{x} \, dx}{2 e^2}\\ &=-\frac{b f m n}{8 e x^2}+\frac{b f^2 m n \log ^2(x)}{4 e^2}-\frac{f m \left (a+b \log \left (c x^n\right )\right )}{4 e x^2}-\frac{f^2 m \log (x) \left (a+b \log \left (c x^n\right )\right )}{2 e^2}+\frac{f^2 m \left (a+b \log \left (c x^n\right )\right ) \log \left (e+f x^2\right )}{4 e^2}-\frac{\left (a+b \log \left (c x^n\right )\right ) \log \left (d \left (e+f x^2\right )^m\right )}{4 x^4}+\frac{1}{8} (b n) \operatorname{Subst}\left (\int \frac{\log \left (d (e+f x)^m\right )}{x^3} \, dx,x,x^2\right )-\frac{\left (b f^2 m n\right ) \operatorname{Subst}\left (\int \frac{\log (e+f x)}{x} \, dx,x,x^2\right )}{8 e^2}\\ &=-\frac{b f m n}{8 e x^2}+\frac{b f^2 m n \log ^2(x)}{4 e^2}-\frac{f m \left (a+b \log \left (c x^n\right )\right )}{4 e x^2}-\frac{f^2 m \log (x) \left (a+b \log \left (c x^n\right )\right )}{2 e^2}-\frac{b f^2 m n \log \left (-\frac{f x^2}{e}\right ) \log \left (e+f x^2\right )}{8 e^2}+\frac{f^2 m \left (a+b \log \left (c x^n\right )\right ) \log \left (e+f x^2\right )}{4 e^2}-\frac{b n \log \left (d \left (e+f x^2\right )^m\right )}{16 x^4}-\frac{\left (a+b \log \left (c x^n\right )\right ) \log \left (d \left (e+f x^2\right )^m\right )}{4 x^4}+\frac{1}{16} (b f m n) \operatorname{Subst}\left (\int \frac{1}{x^2 (e+f x)} \, dx,x,x^2\right )+\frac{\left (b f^3 m n\right ) \operatorname{Subst}\left (\int \frac{\log \left (-\frac{f x}{e}\right )}{e+f x} \, dx,x,x^2\right )}{8 e^2}\\ &=-\frac{b f m n}{8 e x^2}+\frac{b f^2 m n \log ^2(x)}{4 e^2}-\frac{f m \left (a+b \log \left (c x^n\right )\right )}{4 e x^2}-\frac{f^2 m \log (x) \left (a+b \log \left (c x^n\right )\right )}{2 e^2}-\frac{b f^2 m n \log \left (-\frac{f x^2}{e}\right ) \log \left (e+f x^2\right )}{8 e^2}+\frac{f^2 m \left (a+b \log \left (c x^n\right )\right ) \log \left (e+f x^2\right )}{4 e^2}-\frac{b n \log \left (d \left (e+f x^2\right )^m\right )}{16 x^4}-\frac{\left (a+b \log \left (c x^n\right )\right ) \log \left (d \left (e+f x^2\right )^m\right )}{4 x^4}-\frac{b f^2 m n \text{Li}_2\left (1+\frac{f x^2}{e}\right )}{8 e^2}+\frac{1}{16} (b f m n) \operatorname{Subst}\left (\int \left (\frac{1}{e x^2}-\frac{f}{e^2 x}+\frac{f^2}{e^2 (e+f x)}\right ) \, dx,x,x^2\right )\\ &=-\frac{3 b f m n}{16 e x^2}-\frac{b f^2 m n \log (x)}{8 e^2}+\frac{b f^2 m n \log ^2(x)}{4 e^2}-\frac{f m \left (a+b \log \left (c x^n\right )\right )}{4 e x^2}-\frac{f^2 m \log (x) \left (a+b \log \left (c x^n\right )\right )}{2 e^2}+\frac{b f^2 m n \log \left (e+f x^2\right )}{16 e^2}-\frac{b f^2 m n \log \left (-\frac{f x^2}{e}\right ) \log \left (e+f x^2\right )}{8 e^2}+\frac{f^2 m \left (a+b \log \left (c x^n\right )\right ) \log \left (e+f x^2\right )}{4 e^2}-\frac{b n \log \left (d \left (e+f x^2\right )^m\right )}{16 x^4}-\frac{\left (a+b \log \left (c x^n\right )\right ) \log \left (d \left (e+f x^2\right )^m\right )}{4 x^4}-\frac{b f^2 m n \text{Li}_2\left (1+\frac{f x^2}{e}\right )}{8 e^2}\\ \end{align*}
Mathematica [C] time = 0.144964, size = 363, normalized size = 1.46 \[ -\frac{-4 b f^2 m n x^4 \text{PolyLog}\left (2,-\frac{i \sqrt{f} x}{\sqrt{e}}\right )-4 b f^2 m n x^4 \text{PolyLog}\left (2,\frac{i \sqrt{f} x}{\sqrt{e}}\right )+4 a e^2 \log \left (d \left (e+f x^2\right )^m\right )-4 a f^2 m x^4 \log \left (e+f x^2\right )+4 a e f m x^2+8 a f^2 m x^4 \log (x)+4 b e^2 \log \left (c x^n\right ) \log \left (d \left (e+f x^2\right )^m\right )-4 b f^2 m x^4 \log \left (c x^n\right ) \log \left (e+f x^2\right )+4 b e f m x^2 \log \left (c x^n\right )+8 b f^2 m x^4 \log (x) \log \left (c x^n\right )+b e^2 n \log \left (d \left (e+f x^2\right )^m\right )-4 b f^2 m n x^4 \log (x) \log \left (1-\frac{i \sqrt{f} x}{\sqrt{e}}\right )-4 b f^2 m n x^4 \log (x) \log \left (1+\frac{i \sqrt{f} x}{\sqrt{e}}\right )-b f^2 m n x^4 \log \left (e+f x^2\right )+4 b f^2 m n x^4 \log (x) \log \left (e+f x^2\right )+3 b e f m n x^2-4 b f^2 m n x^4 \log ^2(x)+2 b f^2 m n x^4 \log (x)}{16 e^2 x^4} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.368, size = 2313, normalized size = 9.3 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{{\left (b{\left (n + 4 \, \log \left (c\right )\right )} + 4 \, b \log \left (x^{n}\right ) + 4 \, a\right )} \log \left ({\left (f x^{2} + e\right )}^{m}\right )}{16 \, x^{4}} + \int \frac{8 \, b e \log \left (c\right ) \log \left (d\right ) +{\left (4 \,{\left (f m + 2 \, f \log \left (d\right )\right )} a +{\left (f m n + 4 \,{\left (f m + 2 \, f \log \left (d\right )\right )} \log \left (c\right )\right )} b\right )} x^{2} + 8 \, a e \log \left (d\right ) + 4 \,{\left ({\left (f m + 2 \, f \log \left (d\right )\right )} b x^{2} + 2 \, b e \log \left (d\right )\right )} \log \left (x^{n}\right )}{8 \,{\left (f x^{7} + e x^{5}\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (b \log \left (c x^{n}\right ) + a\right )} \log \left ({\left (f x^{2} + e\right )}^{m} d\right )}{x^{5}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \log \left (c x^{n}\right ) + a\right )} \log \left ({\left (f x^{2} + e\right )}^{m} d\right )}{x^{5}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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